And $35,000 an inch on weekends?
The answer is below the fold.
Snow removal in Danbury, Conn. That’s according to Mayor Mark Boughton. You’ve got to like a mayor who has the dollars-per-inch figure ready when a reporter calls.
And $35,000 an inch on weekends?
The answer is below the fold.
Snow removal in Danbury, Conn. That’s according to Mayor Mark Boughton. You’ve got to like a mayor who has the dollars-per-inch figure ready when a reporter calls.
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Spitzer’s hooker.
Thought it was going to be related to male prostitutes…
But it’s obviously not a linear relationship. There’s a fixed cost of sending the snowploughs out to begin with, and if it’s deep enough then the lower layers will start to compact and presumably be more expensive to clear, and if it’s really deep it will start to melt before you get to all of it….
Interesting, but wouldn’t volume (cubic feet, for instance) be a better measure of snow removal?
Todd S @4: Since the area to be cleared is presumed fixed (length x width of roads & parking lots), depth is directly proportional to volume. So if the cost is linear with volume, it is also linear with depth.
Is that an inch of snow that falls or an inch of roadway cleared of snow?
Ariana, it has to be a snowfall measure. An inch of roadway would rack up astronomical costs, even disregarding road width. A 100-foot stretch of road would cost $30 million if it was an inch of road.
On weekdays.
Football.